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4n^2-70n+304=0
a = 4; b = -70; c = +304;
Δ = b2-4ac
Δ = -702-4·4·304
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-6}{2*4}=\frac{64}{8} =8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+6}{2*4}=\frac{76}{8} =9+1/2 $
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